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Display information for equation id:math.2730.7 on revision:2730

* Page found: Prüfungsfragen:Elektrodynamik (eq math.2730.7)

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TeX (original user input): 

\mathbf A (\mathbf r)= \frac{1}{4\pi} \int_{V} \frac{\mathbf v(\mathbf r \,')}{\left|\mathbf r-\mathbf r \,'\right|}\,d^3\mathbf r \,'

TeX (checked): 

\mathbf {A} (\mathbf {r} )={\frac {1}{4\pi }}\int _{V}{\frac {\mathbf {v} (\mathbf {r} \,')}{\left|\mathbf {r} -\mathbf {r} \,'\right|}}\,d^{3}\mathbf {r} \,'

LaTeXML (experimental; uses MathML) rendering

MathML (9.517 KB / 1.506 KB) :

𝐀 ⁢ ( 𝐫 ) = 1 4 ⁢ π ⁢ ∫ V 𝐯 ⁢ ( 𝐫 ′ ) | 𝐫 - 𝐫 ′ | ⁢ d 3 ⁢ 𝐫 ′ 𝐀 𝐫 1 4 𝜋 subscript 𝑉 𝐯 superscript 𝐫 ′ 𝐫 superscript 𝐫 ′ superscript 𝑑 3 superscript 𝐫 ′ {\displaystyle{\displaystyle\mathbf{A}(\mathbf{r})=\frac{1}{4\pi}\int_{V}\frac% {\mathbf{v}(\mathbf{r}\,^{\prime})}{\left|\mathbf{r}-\mathbf{r}\,^{\prime}% \right|}\,d^{3}\mathbf{r}\,^{\prime}}} 
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MathML (2.714 KB / 610 B) :

A ( r ) = 1 4 π ∫ V v ( r ′ ) | r − r ′ | d 3 r ′ {\displaystyle \mathbf {A} (\mathbf {r} )={\frac {1}{4\pi }}\int _{V}{\frac {\mathbf {v} (\mathbf {r} \,')}{\left|\mathbf {r} -\mathbf {r} \,'\right|}}\,d^{3}\mathbf {r} \,'} 
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{\displaystyle \mathbf {A} (\mathbf {r} )={\frac {1}{4\pi }}\int _{V}{\frac {\mathbf {v} (\mathbf {r} \,')}{\left|\mathbf {r} -\mathbf {r} \,'\right|}}\,d^{3}\mathbf {r} \,'}

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