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Display information for equation id:math.2729.6 on revision:2729

* Page found: Prüfungsfragen:Elektrodynamik (eq math.2729.6)

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Hash: 725ba91bf01246a8145b5cf389c95a67

TeX (original user input): 

\mathbf E (\mathbf r,t)=-{\rm grad}\phi(\mathbf r,t)-\frac{{\partial\mathbf A}(\mathbf r,t)}{\partial t}

TeX (checked): 

\mathbf {E} (\mathbf {r} ,t)=-{\rm {grad}}\phi (\mathbf {r} ,t)-{\frac {{\partial \mathbf {A} }(\mathbf {r} ,t)}{\partial t}}

LaTeXML (experimental; uses MathML) rendering

MathML (6.52 KB / 1.126 KB) :

𝐄 ⁢ ( 𝐫 , t ) = - grad ⁢ ϕ ⁢ ( 𝐫 , t ) - ∂ ⁡ 𝐀 ⁢ ( 𝐫 , t ) ∂ ⁡ t 𝐄 𝐫 𝑡 grad italic-ϕ 𝐫 𝑡 𝐀 𝐫 𝑡 𝑡 {\displaystyle{\displaystyle\mathbf{E}(\mathbf{r},t)=-{\rm grad}\phi(\mathbf{r% },t)-\frac{{\partial\mathbf{A}}(\mathbf{r},t)}{\partial t}}} 
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SVG (0 B / 8 B) :


SVG (MathML can be enabled via browser plugin) rendering

MathML (2.202 KB / 507 B) :

E ( r , t ) = − g r a d ϕ ( r , t ) − ∂ A ( r , t ) ∂ t {\displaystyle \mathbf {E} (\mathbf {r} ,t)=-{\rm {grad}}\phi (\mathbf {r} ,t)-{\frac {{\partial \mathbf {A} }(\mathbf {r} ,t)}{\partial t}}} 
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SVG (9.075 KB / 3.806 KB) :

{\displaystyle \mathbf {E} (\mathbf {r} ,t)=-{\rm {grad}}\phi (\mathbf {r} ,t)-{\frac {{\partial \mathbf {A} }(\mathbf {r} ,t)}{\partial t}}}

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