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Display information for equation id:math.2578.6 on revision:2578

* Page found: Ferromagnetismus (eq math.2578.6)

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TeX (original user input):

\begin{align}

& Z=\sum\limits_{{{m}_{l}}=-l}^{l}{{}}\exp \left( \beta \mu B{{m}_{l}} \right) \\

& \nu :={{m}_{l}}+l \\

& \Rightarrow Z=\exp \left( -\beta \mu Bl \right)\sum\limits_{\nu =0}^{2l}{{}}{{\left( \exp \left( \beta \mu B \right) \right)}^{\nu }}=\exp \left( -\beta \mu Bl \right)\frac{\exp \left( \beta \mu B\left( 2l+1 \right) \right)-1}{\exp \left( \beta \mu B \right)-1}=\frac{\sinh \left( \beta \mu B\left( l+\frac{1}{2} \right) \right)}{\sinh \left( \frac{1}{2}\beta \mu B \right)} \\

\end{align}

TeX (checked):

{\begin{aligned}&Z=\sum \limits _{{{m}_{l}}=-l}^{l}{}\exp \left(\beta \mu B{{m}_{l}}\right)\\&\nu :={{m}_{l}}+l\\&\Rightarrow Z=\exp \left(-\beta \mu Bl\right)\sum \limits _{\nu =0}^{2l}{}{{\left(\exp \left(\beta \mu B\right)\right)}^{\nu }}=\exp \left(-\beta \mu Bl\right){\frac {\exp \left(\beta \mu B\left(2l+1\right)\right)-1}{\exp \left(\beta \mu B\right)-1}}={\frac {\sinh \left(\beta \mu B\left(l+{\frac {1}{2}}\right)\right)}{\sinh \left({\frac {1}{2}}\beta \mu B\right)}}\\\end{aligned}}

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Z=ml=llexp(βμBml)ν:=ml+lZ=exp(βμBl)ν=02l(exp(βμB))ν=exp(βμBl)exp(βμB(2l+1))1exp(βμB)1=sinh(βμB(l+12))sinh(12βμB)
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Identifiers

  • Z
  • ml
  • l
  • l
  • β
  • μ
  • B
  • ml
  • ν
  • ml
  • l
  • Z
  • β
  • μ
  • B
  • l
  • ν
  • l
  • β
  • μ
  • B
  • ν
  • β
  • μ
  • B
  • l
  • β
  • μ
  • B
  • l
  • β
  • μ
  • B
  • β
  • μ
  • B
  • l
  • β
  • μ
  • B

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