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Display information for equation id:math.2546.50 on revision:2546

* Page found: Das ideale Fermigas (eq math.2546.50)

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Hash: 9426e6878a764f9381f6e4770a6f7203

TeX (original user input):

\begin{align}

& \int_{-\infty }^{\infty }{{}}dx\frac{{{e}^{x}}}{{{\left( {{e}^{x}}+1 \right)}^{2}}}=\left[ \frac{-1}{\left( {{e}^{x}}+1 \right)} \right]_{-\infty }^{\infty }=1 \\

& \int_{-\infty }^{\infty }{{}}dx\frac{x{{e}^{x}}}{{{\left( {{e}^{x}}+1 \right)}^{2}}}=0\quad da\ Integrand\ ungerade \\

& \int_{-\infty }^{\infty }{{}}dx{{x}^{2}}\frac{{{e}^{x}}}{{{\left( {{e}^{x}}+1 \right)}^{2}}}:=I \\

\end{align}

TeX (checked):

{\begin{aligned}&\int _{-\infty }^{\infty }{}dx{\frac {{e}^{x}}{{\left({{e}^{x}}+1\right)}^{2}}}=\left[{\frac {-1}{\left({{e}^{x}}+1\right)}}\right]_{-\infty }^{\infty }=1\\&\int _{-\infty }^{\infty }{}dx{\frac {x{{e}^{x}}}{{\left({{e}^{x}}+1\right)}^{2}}}=0\quad da\ Integrand\ ungerade\\&\int _{-\infty }^{\infty }{}dx{{x}^{2}}{\frac {{e}^{x}}{{\left({{e}^{x}}+1\right)}^{2}}}:=I\\\end{aligned}}

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dxex(ex+1)2=[1(ex+1)]=1dxxex(ex+1)2=0daIntegrandungeradedxx2ex(ex+1)2:=I
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