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Display information for equation id:math.2516.2 on revision:2516

* Page found: Phasenübergänge (eq math.2516.2)

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TeX (original user input):

\begin{align}

& {{\left( \frac{\partial f}{\partial v} \right)}_{T}}=-p \\

& \Rightarrow \int_{v\acute{\ }}^{v\acute{\ }\acute{\ }}{{}}\left( \frac{\partial f}{\partial v} \right)dv+\left( v\acute{\ }\acute{\ }-v\acute{\ } \right)P=0 \\

& \left( v\acute{\ }\acute{\ }-v\acute{\ } \right)P=-\int_{v\acute{\ }}^{v\acute{\ }\acute{\ }}{{}}\left( \frac{\partial f}{\partial v} \right)dv=\int_{v\acute{\ }}^{v\acute{\ }\acute{\ }}{{}}pdv \\

\end{align}

TeX (checked):

{\begin{aligned}&{{\left({\frac {\partial f}{\partial v}}\right)}_{T}}=-p\\&\Rightarrow \int _{v{\acute {\ }}}^{v{\acute {\ }}{\acute {\ }}}{}\left({\frac {\partial f}{\partial v}}\right)dv+\left(v{\acute {\ }}{\acute {\ }}-v{\acute {\ }}\right)P=0\\&\left(v{\acute {\ }}{\acute {\ }}-v{\acute {\ }}\right)P=-\int _{v{\acute {\ }}}^{v{\acute {\ }}{\acute {\ }}}{}\left({\frac {\partial f}{\partial v}}\right)dv=\int _{v{\acute {\ }}}^{v{\acute {\ }}{\acute {\ }}}{}pdv\\\end{aligned}}

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(fv)T=pv´v´´(fv)dv+(v´´v´)P=0(v´´v´)P=v´v´´(fv)dv=v´v´´pdv
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