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Display information for equation id:math.1728.14 on revision:1728

* Page found: Zeitabhängige Störungsrechnung (eq math.1728.14)

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TeX (original user input):

\begin{align}

& i\hbar \sum\limits_{n}{{}}\frac{d}{dt}{{c}_{n}}(t)\left\langle  m \right|\left| n \right\rangle =\sum\limits_{n}{{}}{{c}_{n}}(t)\left\langle  m \right|\left( {{{\hat{H}}}_{0}}+{{{\hat{H}}}^{1}}(t) \right)\left| n \right\rangle =\sum\limits_{n}{{}}{{c}_{n}}(t)\left\langle  m \right|\left( {{E}_{n}}+{{{\hat{H}}}^{1}}(t) \right)\left| n \right\rangle  \\

& =\sum\limits_{n}{{}}{{c}_{n}}(t)\left( \left\langle  m \right|{{E}_{n}}\left| n \right\rangle +\left\langle  m \right|{{{\hat{H}}}^{1}}(t)\left| n \right\rangle  \right)=\sum\limits_{n}{{}}{{c}_{n}}(t){{E}_{n}}{{\delta }_{mn}}+\sum\limits_{n}{{}}{{c}_{n}}(t)\left\langle  m \right|{{{\hat{H}}}^{1}}(t)\left| n \right\rangle  \\

& \Rightarrow i\hbar \sum\limits_{n}{{}}\frac{d}{dt}{{c}_{n}}(t)\left\langle  m \right|\left| n \right\rangle ={{c}_{m}}(t){{E}_{m}}+\sum\limits_{n}{{}}{{c}_{n}}(t)\left\langle  m \right|{{{\hat{H}}}^{1}}(t)\left| n \right\rangle =i\hbar \frac{d}{dt}{{c}_{m}}(t) \\

\end{align}

TeX (checked):

{\begin{aligned}&i\hbar \sum \limits _{n}{}{\frac {d}{dt}}{{c}_{n}}(t)\left\langle m\right|\left|n\right\rangle =\sum \limits _{n}{}{{c}_{n}}(t)\left\langle m\right|\left({{\hat {H}}_{0}}+{{\hat {H}}^{1}}(t)\right)\left|n\right\rangle =\sum \limits _{n}{}{{c}_{n}}(t)\left\langle m\right|\left({{E}_{n}}+{{\hat {H}}^{1}}(t)\right)\left|n\right\rangle \\&=\sum \limits _{n}{}{{c}_{n}}(t)\left(\left\langle m\right|{{E}_{n}}\left|n\right\rangle +\left\langle m\right|{{\hat {H}}^{1}}(t)\left|n\right\rangle \right)=\sum \limits _{n}{}{{c}_{n}}(t){{E}_{n}}{{\delta }_{mn}}+\sum \limits _{n}{}{{c}_{n}}(t)\left\langle m\right|{{\hat {H}}^{1}}(t)\left|n\right\rangle \\&\Rightarrow i\hbar \sum \limits _{n}{}{\frac {d}{dt}}{{c}_{n}}(t)\left\langle m\right|\left|n\right\rangle ={{c}_{m}}(t){{E}_{m}}+\sum \limits _{n}{}{{c}_{n}}(t)\left\langle m\right|{{\hat {H}}^{1}}(t)\left|n\right\rangle =i\hbar {\frac {d}{dt}}{{c}_{m}}(t)\\\end{aligned}}

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inddtcn(t)m||n=ncn(t)m|(H^0+H^1(t))|n=ncn(t)m|(En+H^1(t))|n=ncn(t)(m|En|n+m|H^1(t)|n)=ncn(t)Enδmn+ncn(t)m|H^1(t)|ninddtcn(t)m||n=cm(t)Em+ncn(t)m|H^1(t)|n=iddtcm(t)
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