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Display information for equation id:math.1656.79 on revision:1656

* Page found: Der harmonische Oszillator (eq math.1656.79)

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\begin{align}
& {{\phi }_{n}}(\xi )=\frac{{{\left( {{a}^{+}} \right)}^{n}}}{\sqrt{n!}}{{\phi }_{0}}(\xi )=\frac{1}{{{i}^{n}}\sqrt{{{2}^{n}}n!}}{{\left( \xi -\frac{d}{d\xi } \right)}^{n}}{{\phi }_{0}}(\xi )=\frac{1}{{{i}^{n}}}\frac{{{A}_{0}}}{\sqrt{{{2}^{n}}n!}}{{\left( -1 \right)}^{n}}{{e}^{\left( \frac{{{\xi }^{2}}}{2} \right)}}\frac{{{d}^{n}}}{{{\left( d\xi  \right)}^{n}}}{{e}^{-{{\xi }^{2}}}} \\
& \frac{{{A}_{0}}}{\sqrt{{{2}^{n}}n!}}:={{A}_{n}} \\
& {{A}_{0}}={{\left( \frac{m\omega }{\hbar \pi } \right)}^{\frac{1}{4}}} \\
& {{\left( -1 \right)}^{n}}{{e}^{\left( \frac{{{\xi }^{2}}}{2} \right)}}\frac{{{d}^{n}}}{{{\left( d\xi  \right)}^{n}}}{{e}^{-{{\xi }^{2}}}}:={{H}_{n}}(\xi ){{e}^{-\frac{{{\xi }^{2}}}{2}}} \\
\end{align}

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ϕn(ξ)=(a+)nn!ϕ0(ξ)=1in2nn!(ξddξ)nϕ0(ξ)=1inA02nn!(1)ne(ξ22)dn(dξ)neξ2A02nn!:=AnA0=(mωπ)14(1)ne(ξ22)dn(dξ)neξ2:=Hn(ξ)eξ22
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