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Display information for equation id:math.1621.37 on revision:1621

* Page found: Operatoren im Hilbertraum (eq math.1621.37)

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Hash: 09ab03b1d03a8c93653f13e1e65fb138

TeX (original user input): 

\left( {{\Psi }_{1}},\hat{F}{{\Psi }_{2}} \right)=\left( {{{\hat{F}}}^{+}}{{\Psi }_{1}},{{\Psi }_{2}} \right)\quad \forall {{\Psi }_{1}},{{\Psi }_{2}}\in H

TeX (checked): 

\left({{\Psi }_{1}},{\hat {F}}{{\Psi }_{2}}\right)=\left({{\hat {F}}^{+}}{{\Psi }_{1}},{{\Psi }_{2}}\right)\quad \forall {{\Psi }_{1}},{{\Psi }_{2}}\in H

LaTeXML (experimental; uses MathML) rendering

MathML (8.961 KB / 1.454 KB) :

( Ψ 1 , F ^ ⁢ Ψ 2 ) = ( F ^ + ⁢ Ψ 1 , Ψ 2 )   ∀ Ψ 1 , Ψ 2 ∈ H formulae-sequence subscript Ψ 1 ^ 𝐹 subscript Ψ 2 superscript ^ 𝐹 subscript Ψ 1 subscript Ψ 2 for-all subscript Ψ 1 subscript Ψ 2 𝐻 {\displaystyle{\displaystyle\left({{\Psi}_{1}},\hat{F}{{\Psi}_{2}}\right)=% \left({{{\hat{F}}}^{+}}{{\Psi}_{1}},{{\Psi}_{2}}\right)\quad\forall{{\Psi}_{1}% },{{\Psi}_{2}}\in H}} 
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MathML (1.358 KB / 324 B) :

(Ψ1,F^Ψ2)=(F^+Ψ1,Ψ2)∀Ψ1,Ψ2∈H
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Identifiers

  • Ψ1
  • F^
  • Ψ2
  • F^
  • Ψ1
  • Ψ2
  • Ψ1
  • Ψ2
  • H

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