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Display information for equation id:math.1587.81 on revision:1587

* Page found: Schrödingergleichung mit äußeren Potenzialen (eq math.1587.81)

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Hash: 039d9aae2a55145aa9ed9aedb4b26731

TeX (original user input): 

\int\limits_{1}^{{}}{\bar{A}(\bar{s})d\bar{s}}-\int\limits_{2}^{{}}{\bar{A}(\bar{s})d\bar{s}}=\oint\limits_{{}}{\bar{A}(\bar{s})d\bar{s}}=\int\limits_{{}}^{{}}{d\bar{f}\ rot\bar{A}}=\int\limits_{{}}^{{}}{\bar{B}d\bar{f}={{\Phi }_{B}}}

LaTeXML (experimental; uses MathML) rendering

MathML (17.825 KB / 2.259 KB) :

∫ 1 A ¯ ⁢ ( s ¯ ) ⁢ 𝑑 s ¯ - ∫ 2 A ¯ ⁢ ( s ¯ ) ⁢ 𝑑 s ¯ = ∮ A ¯ ⁢ ( s ¯ ) ⁢ 𝑑 s ¯ = ∫ 𝑑 f ¯ ⁢ r ⁢ o ⁢ t ⁢ A ¯ = ∫ B ¯ ⁢ 𝑑 f ¯ = Φ B subscript 1 ¯ 𝐴 ¯ 𝑠 differential-d ¯ 𝑠 subscript 2 ¯ 𝐴 ¯ 𝑠 differential-d ¯ 𝑠 contour-integral ¯ 𝐴 ¯ 𝑠 differential-d ¯ 𝑠 differential-d ¯ 𝑓 𝑟 𝑜 𝑡 ¯ 𝐴 ¯ 𝐵 differential-d ¯ 𝑓 subscript Φ 𝐵 {\displaystyle{\displaystyle\int\limits_{1}{\bar{A}(\bar{s})d\bar{s}}-\int% \limits_{2}{\bar{A}(\bar{s})d\bar{s}}=\oint\limits{\bar{A}(\bar{s})d\bar{s}}=% \int\limits{d\bar{f}\ rot\bar{A}}=\int\limits{\bar{B}d\bar{f}={{\Phi}_{B}}}}} 
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    <annotation encoding="application/x-tex" id="p1.1.m1.1c">{\displaystyle{\displaystyle\int\limits_{1}{\bar{A}(\bar{s})d\bar{s}}-\int%
\limits_{2}{\bar{A}(\bar{s})d\bar{s}}=\oint\limits{\bar{A}(\bar{s})d\bar{s}}=%
\int\limits{d\bar{f}\ rot\bar{A}}=\int\limits{\bar{B}d\bar{f}={{\Phi}_{B}}}}}</annotation>
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</math>

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∫1A¯(s¯)ds¯−∫2A¯(s¯)ds¯=∮A¯(s¯)ds¯=∫df¯rotA¯=∫B¯df¯=ΦB
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