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Display information for equation id:math.1583.81 on revision:1583

* Page found: Schrödingergleichung mit äußeren Potenzialen (eq math.1583.81)

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Schrödingergleichung mit äußeren Potenzialen Eq: math.1587.81

Hash: 039d9aae2a55145aa9ed9aedb4b26731

TeX (original user input):

\int\limits_{1}^{{}}{\bar{A}(\bar{s})d\bar{s}}-\int\limits_{2}^{{}}{\bar{A}(\bar{s})d\bar{s}}=\oint\limits_{{}}{\bar{A}(\bar{s})d\bar{s}}=\int\limits_{{}}^{{}}{d\bar{f}\ rot\bar{A}}=\int\limits_{{}}^{{}}{\bar{B}d\bar{f}={{\Phi }_{B}}}

TeX (checked):

\int \limits _{1}^{}{{\bar {A}}({\bar {s}})d{\bar {s}}}-\int \limits _{2}^{}{{\bar {A}}({\bar {s}})d{\bar {s}}}=\oint \limits _{}{{\bar {A}}({\bar {s}})d{\bar {s}}}=\int \limits _{}^{}{d{\bar {f}}\ rot{\bar {A}}}=\int \limits _{}^{}{{\bar {B}}d{\bar {f}}={{\Phi }_{B}}}

LaTeXML (experimental; uses MathML) rendering

MathML (17.825 KB / 2.259 KB) :

{\displaystyle{\displaystyle\int\limits_{1}{\bar{A}(\bar{s})d\bar{s}}-\int% \limits_{2}{\bar{A}(\bar{s})d\bar{s}}=\oint\limits{\bar{A}(\bar{s})d\bar{s}}=% \int\limits{d\bar{f}\ rot\bar{A}}=\int\limits{\bar{B}d\bar{f}={{\Phi}_{B}}}}}

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    <annotation encoding="application/x-tex" id="p1.1.m1.1c">{\displaystyle{\displaystyle\int\limits_{1}{\bar{A}(\bar{s})d\bar{s}}-\int%
\limits_{2}{\bar{A}(\bar{s})d\bar{s}}=\oint\limits{\bar{A}(\bar{s})d\bar{s}}=%
\int\limits{d\bar{f}\ rot\bar{A}}=\int\limits{\bar{B}d\bar{f}={{\Phi}_{B}}}}}</annotation>
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</math>

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MathML (2.842 KB / 396 B) :

\int_{1}^{} \bar{A} (\bar{s}) d \bar{s} - \int_{2}^{} \bar{A} (\bar{s}) d \bar{s} = \oint_{} \bar{A} (\bar{s}) d \bar{s} = \int_{}^{} d \bar{f} r o t \bar{A} = \int_{}^{} \bar{B} d \bar{f} = Φ_{B}

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Identifiers

$\bar{A}$

$\bar{s}$

$\bar{s}$

$\bar{A}$

$\bar{s}$

$\bar{s}$

$\bar{A}$

$\bar{s}$

$d$

$\bar{s}$

$\bar{f}$

$r$

$o$

$t$

$\bar{A}$

$\bar{B}$

$\bar{f}$

$Φ_{B}$

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