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Display information for equation id:math.1438.60 on revision:1438

* Page found: Elektromagnetische Wellen (eq math.1438.60)

Occurrences on the following pages:

Freie Wellenausbreitung im Vakuum Eq: math.2126.56

Hash: 52142e647ec14465b36594203199bded

TeX (original user input):

\begin{align}
& \frac{{{{\bar{E}}}_{1}}}{{{a}_{1}}}\sin {{\delta }_{2}}-\frac{{{{\bar{E}}}_{2}}}{a2}\sin {{\delta }_{1}}=\cos \phi \sin \left( {{\delta }_{2}}-{{\delta }_{1}} \right) \\
& \frac{{{{\bar{E}}}_{1}}}{{{a}_{1}}}\cos {{\delta }_{2}}-\frac{{{{\bar{E}}}_{2}}}{a2}\cos {{\delta }_{1}}=\sin \phi \sin \left( {{\delta }_{2}}-{{\delta }_{1}} \right) \\
& \Rightarrow {{1}^{2}}+{{2}^{2}}\Rightarrow {{\left( \frac{{{{\bar{E}}}_{1}}}{{{a}_{1}}} \right)}^{2}}+{{\left( \frac{{{{\bar{E}}}_{2}}}{a2} \right)}^{2}}-2\frac{{{{\bar{E}}}_{1}}}{{{a}_{1}}}\frac{{{{\bar{E}}}_{2}}}{a2}\cos \left( {{\delta }_{2}}-{{\delta }_{1}} \right)={{\sin }^{2}}\left( {{\delta }_{2}}-{{\delta }_{1}} \right) \\
\end{align}

TeX (checked):

{\begin{aligned}&{\frac {{\bar {E}}_{1}}{{a}_{1}}}\sin {{\delta }_{2}}-{\frac {{\bar {E}}_{2}}{a2}}\sin {{\delta }_{1}}=\cos \phi \sin \left({{\delta }_{2}}-{{\delta }_{1}}\right)\\&{\frac {{\bar {E}}_{1}}{{a}_{1}}}\cos {{\delta }_{2}}-{\frac {{\bar {E}}_{2}}{a2}}\cos {{\delta }_{1}}=\sin \phi \sin \left({{\delta }_{2}}-{{\delta }_{1}}\right)\\&\Rightarrow {{1}^{2}}+{{2}^{2}}\Rightarrow {{\left({\frac {{\bar {E}}_{1}}{{a}_{1}}}\right)}^{2}}+{{\left({\frac {{\bar {E}}_{2}}{a2}}\right)}^{2}}-2{\frac {{\bar {E}}_{1}}{{a}_{1}}}{\frac {{\bar {E}}_{2}}{a2}}\cos \left({{\delta }_{2}}-{{\delta }_{1}}\right)={{\sin }^{2}}\left({{\delta }_{2}}-{{\delta }_{1}}\right)\\\end{aligned}}

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\begin{aligned} \frac{{\bar{E}}_{1}}{a_{1}} \sin δ_{2} - \frac{{\bar{E}}_{2}}{a 2} \sin δ_{1} = \cos ϕ \sin (δ_{2} - δ_{1}) \\ \frac{{\bar{E}}_{1}}{a_{1}} \cos δ_{2} - \frac{{\bar{E}}_{2}}{a 2} \cos δ_{1} = \sin ϕ \sin (δ_{2} - δ_{1}) \\ \Rightarrow 1^{2} + 2^{2} \Rightarrow {(\frac{{\bar{E}}_{1}}{a_{1}})}^{2} + {(\frac{{\bar{E}}_{2}}{a 2})}^{2} - 2 \frac{{\bar{E}}_{1}}{a_{1}} \frac{{\bar{E}}_{2}}{a 2} \cos (δ_{2} - δ_{1}) = \sin^{2} (δ_{2} - δ_{1}) \end{aligned}

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Identifiers

${\bar{E}}_{1}$

$a_{1}$

$δ_{2}$

${\bar{E}}_{2}$

$a$

$δ_{1}$

$ϕ$

$δ_{2}$

$δ_{1}$

${\bar{E}}_{1}$

$a_{1}$

$δ_{2}$

${\bar{E}}_{2}$

$a$

$δ_{1}$

$ϕ$

$δ_{2}$

$δ_{1}$

${\bar{E}}_{1}$

$a_{1}$

${\bar{E}}_{2}$

$a$

${\bar{E}}_{1}$

$a_{1}$

${\bar{E}}_{2}$

$a$

$δ_{2}$

$δ_{1}$

$δ_{2}$

$δ_{1}$

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