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Display information for equation id:math.1347.79 on revision:1347

* Page found: Mechanik des starren Körpers (eq math.1347.79)

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TeX (original user input):

\begin{align}
  & \rho (\bar{x})=\rho (r) \\
 & {{J}_{1}}={{J}_{2}}={{J}_{3}}=:J \\
 & 3J={{J}_{1}}+{{J}_{2}}+{{J}_{3}}=\int_{{}}^{{}}{{{d}^{3}}x}\rho (r)\left[ \left( {{x}_{2}}^{2}+{{x}_{3}}^{2} \right)+\left( {{x}_{1}}^{2}+{{x}_{3}}^{2} \right)+\left( {{x}_{1}}^{2}+{{x}_{2}}^{2} \right) \right]=\int_{{}}^{{}}{{{d}^{3}}x}\rho (r)2{{r}^{2}} \\
 & 3J=2\cdot 4\pi \int_{0}^{R}{dr{{r}^{4}}\rho (r)} \\
\end{align}

TeX (checked):

{\begin{aligned}&\rho ({\bar {x}})=\rho (r)\\&{{J}_{1}}={{J}_{2}}={{J}_{3}}=:J\\&3J={{J}_{1}}+{{J}_{2}}+{{J}_{3}}=\int _{}^{}{{{d}^{3}}x}\rho (r)\left[\left({{x}_{2}}^{2}+{{x}_{3}}^{2}\right)+\left({{x}_{1}}^{2}+{{x}_{3}}^{2}\right)+\left({{x}_{1}}^{2}+{{x}_{2}}^{2}\right)\right]=\int _{}^{}{{{d}^{3}}x}\rho (r)2{{r}^{2}}\\&3J=2\cdot 4\pi \int _{0}^{R}{dr{{r}^{4}}\rho (r)}\\\end{aligned}}

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ρ(x¯)=ρ(r)J1=J2=J3=:J3J=J1+J2+J3=d3xρ(r)[(x22+x32)+(x12+x32)+(x12+x22)]=d3xρ(r)2r23J=24π0Rdrr4ρ(r)
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Calculated based on the variables occurring on the entire Mechanik des starren Körpers page

Identifiers

  • ρ
  • x¯
  • ρ
  • r
  • J1
  • J2
  • J3
  • J
  • J
  • J1
  • J2
  • J3
  • x
  • ρ
  • r
  • x2
  • x3
  • x1
  • x3
  • x1
  • x2
  • x
  • ρ
  • r
  • r
  • J
  • π
  • R
  • r
  • r
  • ρ
  • r

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