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Display information for equation id:math.1199.1068 on revision:1199
* Page found: Elektrodynamik Schöll (eq math.1199.1068)
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Hash: 2b5699358178d343477a7dd31138de17
TeX (original user input):
\begin{align}
& {{\left( \nabla \times \bar{E} \right)}_{2}}=\frac{\partial {{E}_{1}}}{\partial {{x}_{3}}}=-{{{\dot{B}}}_{2}} \\
& \Leftrightarrow i\frac{\omega }{c}\left( n+i\gamma \right){{E}_{1}}=i\omega {{B}_{2}} \\
& \Leftrightarrow {{B}_{2}}=\frac{\left( n+i\gamma \right)}{c}{{E}_{1}}=\frac{\sqrt{{{n}^{2}}+{{\gamma }^{2}}}}{c}{{e}^{i\phi }}{{E}_{1}} \\
\end{align}
TeX (checked):
{\begin{aligned}&{{\left(\nabla \times {\bar {E}}\right)}_{2}}={\frac {\partial {{E}_{1}}}{\partial {{x}_{3}}}}=-{{\dot {B}}_{2}}\\&\Leftrightarrow i{\frac {\omega }{c}}\left(n+i\gamma \right){{E}_{1}}=i\omega {{B}_{2}}\\&\Leftrightarrow {{B}_{2}}={\frac {\left(n+i\gamma \right)}{c}}{{E}_{1}}={\frac {\sqrt {{{n}^{2}}+{{\gamma }^{2}}}}{c}}{{e}^{i\phi }}{{E}_{1}}\\\end{aligned}}
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