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Kernfusion
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Konstanten ;m(<math>^1</math>H ) = 1,008 u ;m(<math>^4</math>He) = 4,003 u ;U = <math>1,66 \times 10^{−27}</math> kg ;c = <math>3 \times 10^8</math> m/s ;1l = 1 dm a) In der Sonne werden vier <math>{}^1_1</math>H-Kerne zu einem <math>{}^4_2</math>He-Kern fusioniert. Unter der Annahme, dass allein dieser Prozess für die Strahlungsleistung der Sonne verantwortlich ist, berechnen Sie, wie viele Wasserstoffkerne in jeder Sekunde umgewandelt werden müssen, damit die Sonne eine Gesamtleistung von <math>P = 3,74 \times 10^{26}</math>W abstrahlen kann. Welcher Masse an Wasserstoffkernen entspricht das? b) Schätzen Sie rechnerisch ab, wie viele Liter Heizöl man verbrennen müsste, um die gleiche Leistung zu erhalten (Heizwert von Heizöl: 42 MJ/kg, Dichte von Heizöl:0,85 g/cm³). {{Klausuraufgabe |KADatum=SS10 |KAAufgabe=2 |KAAbschnitt=K |KAPunkte=7 |KATut=8 }}
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